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python3对list group by

作者:高景洋　日期:2020-12-03 16:07:44　浏览次数:1771

				from operator import itemgetter
			
				from itertools import groupby

			if __name__ == "__main__":
		

						    d1={'name':'zhangsan','age':20,'country':'China'}
					
						    d2={'name':'wangwu','age':19,'country':'USA'}
					
						    d3={'name':'lisi','age':22,'country':'JP'}
					
						    d4={'name':'zhaoliu','age':22,'country':'USA'}
					
						    d5={'name':'pengqi','age':22,'country':'USA'}
					
						    d6={'name':'lijiu','age':22,'country':'China'}
					
						    lst=[d1,d2,d3,d4,d5,d6]
					
						    lst.sort(key=itemgetter('country')) #需要先排序，然后才能groupby。lst排序后自身被改变
					
						    lstg = groupby(lst,itemgetter('country'))
					
						    t = min(lst,key = itemgetter('age'))
					
						    for key,group in lstg:
					
						        for g in group: #group是一个迭代器，包含了所有的分组列表
					
						            print('{} - {}'.format(key,g))

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